37-2(c+4)=2(c+4)+c

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Solution for 37-2(c+4)=2(c+4)+c equation: 



37-2(c+4)=2(c+4)+c

We move all terms to the left:

37-2(c+4)-(2(c+4)+c)=0

We multiply parentheses

-2c-(2(c+4)+c)-8+37=0



We calculate terms in parentheses: -(2(c+4)+c), so:

2(c+4)+c

We add all the numbers together, and all the variables

c+2(c+4)

We multiply parentheses

c+2c+8

We add all the numbers together, and all the variables

3c+8

Back to the equation:

-(3c+8)



We add all the numbers together, and all the variables

-2c-(3c+8)+29=0

We get rid of parentheses

-2c-3c-8+29=0

We add all the numbers together, and all the variables

-5c+21=0

We move all terms containing c to the left, all other terms to the right

-5c=-21

c=-21/-5

c=4+1/5

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