37/5x+3/5x=2

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Solution for 37/5x+3/5x=2 equation:



37/5x+3/5x=2
We move all terms to the left:
37/5x+3/5x-(2)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
We multiply all the terms by the denominator
-2*5x+37+3=0
We add all the numbers together, and all the variables
-2*5x+40=0
Wy multiply elements
-10x+40=0
We move all terms containing x to the left, all other terms to the right
-10x=-40
x=-40/-10
x=+4

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