37=(3x-4)+(2x+1)

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Solution for 37=(3x-4)+(2x+1) equation: 



37=(3x-4)+(2x+1)

We move all terms to the left:

37-((3x-4)+(2x+1))=0



We calculate terms in parentheses: -((3x-4)+(2x+1)), so:

(3x-4)+(2x+1)

We get rid of parentheses

3x+2x-4+1

We add all the numbers together, and all the variables

5x-3

Back to the equation:

-(5x-3)



We get rid of parentheses

-5x+3+37=0

We add all the numbers together, and all the variables

-5x+40=0

We move all terms containing x to the left, all other terms to the right

-5x=-40

x=-40/-5

x=+8

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