37=7(y-3)+4y

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Solution for 37=7(y-3)+4y equation: 



37=7(y-3)+4y

We move all terms to the left:

37-(7(y-3)+4y)=0



We calculate terms in parentheses: -(7(y-3)+4y), so:

7(y-3)+4y

We add all the numbers together, and all the variables

4y+7(y-3)

We multiply parentheses

4y+7y-21

We add all the numbers together, and all the variables

11y-21

Back to the equation:

-(11y-21)



We get rid of parentheses

-11y+21+37=0

We add all the numbers together, and all the variables

-11y+58=0

We move all terms containing y to the left, all other terms to the right

-11y=-58

y=-58/-11

y=5+3/11

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