37=x+(3x-5)+(x+2)

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Solution for 37=x+(3x-5)+(x+2) equation: 



37=x+(3x-5)+(x+2)

We move all terms to the left:

37-(x+(3x-5)+(x+2))=0



We calculate terms in parentheses: -(x+(3x-5)+(x+2)), so:

x+(3x-5)+(x+2)

We get rid of parentheses

x+3x+x-5+2

We add all the numbers together, and all the variables

5x-3

Back to the equation:

-(5x-3)



We get rid of parentheses

-5x+3+37=0

We add all the numbers together, and all the variables

-5x+40=0

We move all terms containing x to the left, all other terms to the right

-5x=-40

x=-40/-5

x=+8

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