37x+1/2-(1x+1/4)=9(4x-7)+5

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Solution for 37x+1/2-(1x+1/4)=9(4x-7)+5 equation: 


x in (-oo:+oo)

37*x-(1*x)+1/2-(1/4) = 9*(4*x-7)+5 // - 9*(4*x-7)+5

37*x-(9*(4*x-7))-(1*x)+1/2-(1/4)-5 = 0

37*x-9*(4*x-7)-x+1/2-1/4-5 = 0

(-9*2*4*(4*x-7))/(2*4)+(2*4*37*x)/(2*4)+(2*4*(-x))/(2*4)+(1*4)/(2*4)+(-1*2)/(2*4)+(-5*2*4)/(2*4) = 0

2*4*37*x-9*2*4*(4*x-7)+2*4*(-x)+1*4-1*2-5*2*4 = 0

8*x-8*x-40-2+4+504 = 0

4-40-2+504 = 0

508-40-2 = 0

506-40 = 0

466 = 0

466/(2*4) = 0

466/(2*4) = 0 // * 2*4

466 = 0

x belongs to the empty set

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