37y=12(3y+33)

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Solution for 37y=12(3y+33) equation: 



37y=12(3y+33)

We move all terms to the left:

37y-(12(3y+33))=0



We calculate terms in parentheses: -(12(3y+33)), so:

12(3y+33)

We multiply parentheses

36y+396

Back to the equation:

-(36y+396)



We get rid of parentheses

37y-36y-396=0

We add all the numbers together, and all the variables

y-396=0

We move all terms containing y to the left, all other terms to the right

y=396

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