38+(6x-6)=2(7x-4)

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Solution for 38+(6x-6)=2(7x-4) equation: 



38+(6x-6)=2(7x-4)

We move all terms to the left:

38+(6x-6)-(2(7x-4))=0

We get rid of parentheses

6x-(2(7x-4))-6+38=0



We calculate terms in parentheses: -(2(7x-4)), so:

2(7x-4)

We multiply parentheses

14x-8

Back to the equation:

-(14x-8)



We add all the numbers together, and all the variables

6x-(14x-8)+32=0

We get rid of parentheses

6x-14x+8+32=0

We add all the numbers together, and all the variables

-8x+40=0

We move all terms containing x to the left, all other terms to the right

-8x=-40

x=-40/-8

x=+5

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