38+8y=2(3y+6)+2(2y+4)

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Solution for 38+8y=2(3y+6)+2(2y+4) equation: 



38+8y=2(3y+6)+2(2y+4)

We move all terms to the left:

38+8y-(2(3y+6)+2(2y+4))=0



We calculate terms in parentheses: -(2(3y+6)+2(2y+4)), so:

2(3y+6)+2(2y+4)

We multiply parentheses

6y+4y+12+8

We add all the numbers together, and all the variables

10y+20

Back to the equation:

-(10y+20)



We get rid of parentheses

8y-10y-20+38=0

We add all the numbers together, and all the variables

-2y+18=0

We move all terms containing y to the left, all other terms to the right

-2y=-18

y=-18/-2

y=+9

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