38-(2c+4)=4(c+5)+5

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Solution for 38-(2c+4)=4(c+5)+5 equation: 



38-(2c+4)=4(c+5)+5

We move all terms to the left:

38-(2c+4)-(4(c+5)+5)=0

We get rid of parentheses

-2c-(4(c+5)+5)-4+38=0



We calculate terms in parentheses: -(4(c+5)+5), so:

4(c+5)+5

We multiply parentheses

4c+20+5

We add all the numbers together, and all the variables

4c+25

Back to the equation:

-(4c+25)



We add all the numbers together, and all the variables

-2c-(4c+25)+34=0

We get rid of parentheses

-2c-4c-25+34=0

We add all the numbers together, and all the variables

-6c+9=0

We move all terms containing c to the left, all other terms to the right

-6c=-9

c=-9/-6

c=1+1/2

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