38-(3c+4)=(29c+5)+c

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Solution for 38-(3c+4)=(29c+5)+c equation: 



38-(3c+4)=(29c+5)+c

We move all terms to the left:

38-(3c+4)-((29c+5)+c)=0

We get rid of parentheses

-3c-((29c+5)+c)-4+38=0



We calculate terms in parentheses: -((29c+5)+c), so:

(29c+5)+c

We add all the numbers together, and all the variables

c+(29c+5)

We get rid of parentheses

c+29c+5

We add all the numbers together, and all the variables

30c+5

Back to the equation:

-(30c+5)



We add all the numbers together, and all the variables

-3c-(30c+5)+34=0

We get rid of parentheses

-3c-30c-5+34=0

We add all the numbers together, and all the variables

-33c+29=0

We move all terms containing c to the left, all other terms to the right

-33c=-29

c=-29/-33

c=29/33

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