38-3(3c+4)=2(c+3)=c

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Solution for 38-3(3c+4)=2(c+3)=c equation: 



38-3(3c+4)=2(c+3)=c

We move all terms to the left:

38-3(3c+4)-(2(c+3))=0

We multiply parentheses

-9c-(2(c+3))-12+38=0



We calculate terms in parentheses: -(2(c+3)), so:

2(c+3)

We multiply parentheses

2c+6

Back to the equation:

-(2c+6)



We add all the numbers together, and all the variables

-9c-(2c+6)+26=0

We get rid of parentheses

-9c-2c-6+26=0

We add all the numbers together, and all the variables

-11c+20=0

We move all terms containing c to the left, all other terms to the right

-11c=-20

c=-20/-11

c=1+9/11

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