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38/48x+50=x
We move all terms to the left:
38/48x+50-(x)=0
Domain of the equation: 48x!=0We add all the numbers together, and all the variables
x!=0/48
x!=0
x∈R
-1x+38/48x+50=0
We multiply all the terms by the denominator
-1x*48x+50*48x+38=0
Wy multiply elements
-48x^2+2400x+38=0
a = -48; b = 2400; c = +38;
Δ = b2-4ac
Δ = 24002-4·(-48)·38
Δ = 5767296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5767296}=\sqrt{64*90114}=\sqrt{64}*\sqrt{90114}=8\sqrt{90114}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2400)-8\sqrt{90114}}{2*-48}=\frac{-2400-8\sqrt{90114}}{-96} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2400)+8\sqrt{90114}}{2*-48}=\frac{-2400+8\sqrt{90114}}{-96} $
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