38/c-7=12,c=

Solution for 38/c-7=12,c= equation:

38/c-7=12.c=

We move all terms to the left:

38/c-7-(12.c)=0


Domain of the equation: c!=0

c∈R


We add all the numbers together, and all the variables

38/c-(+12.c)-7=0

We get rid of parentheses

38/c-12.c-7=0

We multiply all the terms by the denominator


-(12.c)*c-7*c+38=0

We add all the numbers together, and all the variables

-(+12.c)*c-7*c+38=0

We add all the numbers together, and all the variables

-7c-(+12.c)*c+38=0

We multiply parentheses

-12c^2-7c+38=0

a = -12; b = -7; c = +38;
Δ = b2-4ac
Δ = -72-4·(-12)·38
Δ = 1873
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{1873}}{2*-12}=\frac{7-\sqrt{1873}}{-24}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{1873}}{2*-12}=\frac{7+\sqrt{1873}}{-24}
$