380=(2x+3)x

Solution for 380=(2x+3)x equation:

380=(2x+3)x

We move all terms to the left:

380-((2x+3)x)=0


We calculate terms in parentheses: -((2x+3)x), so:

(2x+3)x

We multiply parentheses

2x^2+3x

Back to the equation:

-(2x^2+3x)


We get rid of parentheses

-2x^2-3x+380=0

a = -2; b = -3; c = +380;
Δ = b2-4ac
Δ = -32-4·(-2)·380
Δ = 3049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{3049}}{2*-2}=\frac{3-\sqrt{3049}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{3049}}{2*-2}=\frac{3+\sqrt{3049}}{-4}
$