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3846.5=3.14r^2
We move all terms to the left:
3846.5-(3.14r^2)=0
We get rid of parentheses
-3.14r^2+3846.5=0
a = -3.14; b = 0; c = +3846.5;
Δ = b2-4ac
Δ = 02-4·(-3.14)·3846.5
Δ = 48312.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{48312.04}}{2*-3.14}=\frac{0-\sqrt{48312.04}}{-6.28} =-\frac{\sqrt{}}{-6.28} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{48312.04}}{2*-3.14}=\frac{0+\sqrt{48312.04}}{-6.28} =\frac{\sqrt{}}{-6.28} $
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