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384=2x(x-4)
We move all terms to the left:
384-(2x(x-4))=0
We calculate terms in parentheses: -(2x(x-4)), so:We get rid of parentheses
2x(x-4)
We multiply parentheses
2x^2-8x
Back to the equation:
-(2x^2-8x)
-2x^2+8x+384=0
a = -2; b = 8; c = +384;
Δ = b2-4ac
Δ = 82-4·(-2)·384
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-56}{2*-2}=\frac{-64}{-4} =+16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+56}{2*-2}=\frac{48}{-4} =-12 $
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