38=-3(4y+2)=y

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Solution for 38=-3(4y+2)=y equation: 



38=-3(4y+2)=y

We move all terms to the left:

38-(-3(4y+2))=0



We calculate terms in parentheses: -(-3(4y+2)), so:

-3(4y+2)

We multiply parentheses

-12y-6

Back to the equation:

-(-12y-6)



We get rid of parentheses

12y+6+38=0

We add all the numbers together, and all the variables

12y+44=0

We move all terms containing y to the left, all other terms to the right

12y=-44

y=-44/12

y=-3+2/3

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