38=10b-3+3b+1

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Solution for 38=10b-3+3b+1 equation: 



38=10b-3+3b+1

We move all terms to the left:

38-(10b-3+3b+1)=0

We add all the numbers together, and all the variables

-(13b-2)+38=0

We get rid of parentheses

-13b+2+38=0

We add all the numbers together, and all the variables

-13b+40=0

We move all terms containing b to the left, all other terms to the right

-13b=-40

b=-40/-13

b=3+1/13

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