38=2(3x+3)+3x

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Solution for 38=2(3x+3)+3x equation: 



38=2(3x+3)+3x

We move all terms to the left:

38-(2(3x+3)+3x)=0



We calculate terms in parentheses: -(2(3x+3)+3x), so:

2(3x+3)+3x

We add all the numbers together, and all the variables

3x+2(3x+3)

We multiply parentheses

3x+6x+6

We add all the numbers together, and all the variables

9x+6

Back to the equation:

-(9x+6)



We get rid of parentheses

-9x-6+38=0

We add all the numbers together, and all the variables

-9x+32=0

We move all terms containing x to the left, all other terms to the right

-9x=-32

x=-32/-9

x=3+5/9

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