38=2(y-6)+3y

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Solution for 38=2(y-6)+3y equation: 



38=2(y-6)+3y

We move all terms to the left:

38-(2(y-6)+3y)=0



We calculate terms in parentheses: -(2(y-6)+3y), so:

2(y-6)+3y

We add all the numbers together, and all the variables

3y+2(y-6)

We multiply parentheses

3y+2y-12

We add all the numbers together, and all the variables

5y-12

Back to the equation:

-(5y-12)



We get rid of parentheses

-5y+12+38=0

We add all the numbers together, and all the variables

-5y+50=0

We move all terms containing y to the left, all other terms to the right

-5y=-50

y=-50/-5

y=+10

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