38=3(y-4)+7y

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Solution for 38=3(y-4)+7y equation: 



38=3(y-4)+7y

We move all terms to the left:

38-(3(y-4)+7y)=0



We calculate terms in parentheses: -(3(y-4)+7y), so:

3(y-4)+7y

We add all the numbers together, and all the variables

7y+3(y-4)

We multiply parentheses

7y+3y-12

We add all the numbers together, and all the variables

10y-12

Back to the equation:

-(10y-12)



We get rid of parentheses

-10y+12+38=0

We add all the numbers together, and all the variables

-10y+50=0

We move all terms containing y to the left, all other terms to the right

-10y=-50

y=-50/-10

y=+5

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