38=3(y-4)-8y

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Solution for 38=3(y-4)-8y equation: 



38=3(y-4)-8y

We move all terms to the left:

38-(3(y-4)-8y)=0



We calculate terms in parentheses: -(3(y-4)-8y), so:

3(y-4)-8y

We add all the numbers together, and all the variables

-8y+3(y-4)

We multiply parentheses

-8y+3y-12

We add all the numbers together, and all the variables

-5y-12

Back to the equation:

-(-5y-12)



We get rid of parentheses

5y+12+38=0

We add all the numbers together, and all the variables

5y+50=0

We move all terms containing y to the left, all other terms to the right

5y=-50

y=-50/5

y=-10

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