38=5(2b-3)+1

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Solution for 38=5(2b-3)+1 equation: 



38=5(2b-3)+1

We move all terms to the left:

38-(5(2b-3)+1)=0



We calculate terms in parentheses: -(5(2b-3)+1), so:

5(2b-3)+1

We multiply parentheses

10b-15+1

We add all the numbers together, and all the variables

10b-14

Back to the equation:

-(10b-14)



We get rid of parentheses

-10b+14+38=0

We add all the numbers together, and all the variables

-10b+52=0

We move all terms containing b to the left, all other terms to the right

-10b=-52

b=-52/-10

b=5+1/5

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