38=5(2b-3)=3b+1

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Solution for 38=5(2b-3)=3b+1 equation: 



38=5(2b-3)=3b+1

We move all terms to the left:

38-(5(2b-3))=0



We calculate terms in parentheses: -(5(2b-3)), so:

5(2b-3)

We multiply parentheses

10b-15

Back to the equation:

-(10b-15)



We get rid of parentheses

-10b+15+38=0

We add all the numbers together, and all the variables

-10b+53=0

We move all terms containing b to the left, all other terms to the right

-10b=-53

b=-53/-10

b=5+3/10

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