38=6(y-2)+4y

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Solution for 38=6(y-2)+4y equation: 



38=6(y-2)+4y

We move all terms to the left:

38-(6(y-2)+4y)=0



We calculate terms in parentheses: -(6(y-2)+4y), so:

6(y-2)+4y

We add all the numbers together, and all the variables

4y+6(y-2)

We multiply parentheses

4y+6y-12

We add all the numbers together, and all the variables

10y-12

Back to the equation:

-(10y-12)



We get rid of parentheses

-10y+12+38=0

We add all the numbers together, and all the variables

-10y+50=0

We move all terms containing y to the left, all other terms to the right

-10y=-50

y=-50/-10

y=+5

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