38=8(y-4)+2y

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Solution for 38=8(y-4)+2y equation: 



38=8(y-4)+2y

We move all terms to the left:

38-(8(y-4)+2y)=0



We calculate terms in parentheses: -(8(y-4)+2y), so:

8(y-4)+2y

We add all the numbers together, and all the variables

2y+8(y-4)

We multiply parentheses

2y+8y-32

We add all the numbers together, and all the variables

10y-32

Back to the equation:

-(10y-32)



We get rid of parentheses

-10y+32+38=0

We add all the numbers together, and all the variables

-10y+70=0

We move all terms containing y to the left, all other terms to the right

-10y=-70

y=-70/-10

y=+7

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