39(1+x)=15(3+x)

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Solution for 39(1+x)=15(3+x) equation: 



39(1+x)=15(3+x)

We move all terms to the left:

39(1+x)-(15(3+x))=0

We add all the numbers together, and all the variables

39(x+1)-(15(x+3))=0

We multiply parentheses

39x-(15(x+3))+39=0



We calculate terms in parentheses: -(15(x+3)), so:

15(x+3)

We multiply parentheses

15x+45

Back to the equation:

-(15x+45)



We get rid of parentheses

39x-15x-45+39=0

We add all the numbers together, and all the variables

24x-6=0

We move all terms containing x to the left, all other terms to the right

24x=6

x=6/24

x=1/4

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