39(1/5)=9/5c+32

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Solution for 39(1/5)=9/5c+32 equation: 



39(1/5)=9/5c+32

We move all terms to the left:

39(1/5)-(9/5c+32)=0



Domain of the equation: 5c+32)!=0

c∈R



We add all the numbers together, and all the variables

-(9/5c+32)+39(+1/5)=0

We multiply parentheses

-(9/5c+32)+1/5*39=0

We get rid of parentheses

-9/5c-32+1/5*39=0

We calculate fractions

There is no solution for this equation

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