39(3x+1)=26(5x-2)

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Solution for 39(3x+1)=26(5x-2) equation: 



39(3x+1)=26(5x-2)

We move all terms to the left:

39(3x+1)-(26(5x-2))=0

We multiply parentheses

117x-(26(5x-2))+39=0



We calculate terms in parentheses: -(26(5x-2)), so:

26(5x-2)

We multiply parentheses

130x-52

Back to the equation:

-(130x-52)



We get rid of parentheses

117x-130x+52+39=0

We add all the numbers together, and all the variables

-13x+91=0

We move all terms containing x to the left, all other terms to the right

-13x=-91

x=-91/-13

x=+7

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