39(x+2)+x=4(x-1)+10

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Solution for 39(x+2)+x=4(x-1)+10 equation: 



39(x+2)+x=4(x-1)+10

We move all terms to the left:

39(x+2)+x-(4(x-1)+10)=0

We add all the numbers together, and all the variables

x+39(x+2)-(4(x-1)+10)=0

We multiply parentheses

x+39x-(4(x-1)+10)+78=0



We calculate terms in parentheses: -(4(x-1)+10), so:

4(x-1)+10

We multiply parentheses

4x-4+10

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We add all the numbers together, and all the variables

40x-(4x+6)+78=0

We get rid of parentheses

40x-4x-6+78=0

We add all the numbers together, and all the variables

36x+72=0

We move all terms containing x to the left, all other terms to the right

36x=-72

x=-72/36

x=-2

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