39+(-19+3x)+(X+28)=180

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Solution for 39+(-19+3x)+(X+28)=180 equation: 



39+(-19+3x)+(x+28)=180

We move all terms to the left:

39+(-19+3x)+(x+28)-(180)=0

We add all the numbers together, and all the variables

(3x-19)+(x+28)+39-180=0

We add all the numbers together, and all the variables

(3x-19)+(x+28)-141=0

We get rid of parentheses

3x+x-19+28-141=0

We add all the numbers together, and all the variables

4x-132=0

We move all terms containing x to the left, all other terms to the right

4x=132

x=132/4

x=33

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