39+3y-9=11y-12-2y

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Solution for 39+3y-9=11y-12-2y equation:



39+3y-9=11y-12-2y
We move all terms to the left:
39+3y-9-(11y-12-2y)=0
We add all the numbers together, and all the variables
3y-(9y-12)+39-9=0
We add all the numbers together, and all the variables
3y-(9y-12)+30=0
We get rid of parentheses
3y-9y+12+30=0
We add all the numbers together, and all the variables
-6y+42=0
We move all terms containing y to the left, all other terms to the right
-6y=-42
y=-42/-6
y=+7

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