39-2+5y-3(y+2)=4(5y-7)-5(y-1)-18y+20

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Solution for 39-2+5y-3(y+2)=4(5y-7)-5(y-1)-18y+20 equation:



39-2+5y-3(y+2)=4(5y-7)-5(y-1)-18y+20
We move all terms to the left:
39-2+5y-3(y+2)-(4(5y-7)-5(y-1)-18y+20)=0
We add all the numbers together, and all the variables
5y-3(y+2)-(4(5y-7)-5(y-1)-18y+20)+37=0
We multiply parentheses
5y-3y-(4(5y-7)-5(y-1)-18y+20)-6+37=0
We calculate terms in parentheses: -(4(5y-7)-5(y-1)-18y+20), so:
4(5y-7)-5(y-1)-18y+20
We add all the numbers together, and all the variables
-18y+4(5y-7)-5(y-1)+20
We multiply parentheses
-18y+20y-5y-28+5+20
We add all the numbers together, and all the variables
-3y-3
Back to the equation:
-(-3y-3)
We add all the numbers together, and all the variables
2y-(-3y-3)+31=0
We get rid of parentheses
2y+3y+3+31=0
We add all the numbers together, and all the variables
5y+34=0
We move all terms containing y to the left, all other terms to the right
5y=-34
y=-34/5
y=-6+4/5

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