39-2b=3(b-1)+2

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Solution for 39-2b=3(b-1)+2 equation:



39-2b=3(b-1)+2
We move all terms to the left:
39-2b-(3(b-1)+2)=0
We calculate terms in parentheses: -(3(b-1)+2), so:
3(b-1)+2
We multiply parentheses
3b-3+2
We add all the numbers together, and all the variables
3b-1
Back to the equation:
-(3b-1)
We get rid of parentheses
-2b-3b+1+39=0
We add all the numbers together, and all the variables
-5b+40=0
We move all terms containing b to the left, all other terms to the right
-5b=-40
b=-40/-5
b=+8

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