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392/x=x
We move all terms to the left:
392/x-(x)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
-1x+392/x=0
We multiply all the terms by the denominator
-1x*x+392=0
Wy multiply elements
-1x^2+392=0
a = -1; b = 0; c = +392;
Δ = b2-4ac
Δ = 02-4·(-1)·392
Δ = 1568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1568}=\sqrt{784*2}=\sqrt{784}*\sqrt{2}=28\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28\sqrt{2}}{2*-1}=\frac{0-28\sqrt{2}}{-2} =-\frac{28\sqrt{2}}{-2} =-\frac{14\sqrt{2}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28\sqrt{2}}{2*-1}=\frac{0+28\sqrt{2}}{-2} =\frac{28\sqrt{2}}{-2} =\frac{14\sqrt{2}}{-1} $
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