39=(2x+5)+(x-3)+(3x+1)

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Solution for 39=(2x+5)+(x-3)+(3x+1) equation: 



39=(2x+5)+(x-3)+(3x+1)

We move all terms to the left:

39-((2x+5)+(x-3)+(3x+1))=0



We calculate terms in parentheses: -((2x+5)+(x-3)+(3x+1)), so:

(2x+5)+(x-3)+(3x+1)

We get rid of parentheses

2x+x+3x+5-3+1

We add all the numbers together, and all the variables

6x+3

Back to the equation:

-(6x+3)



We get rid of parentheses

-6x-3+39=0

We add all the numbers together, and all the variables

-6x+36=0

We move all terms containing x to the left, all other terms to the right

-6x=-36

x=-36/-6

x=+6

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