39=2b+3(3b+2)

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Solution for 39=2b+3(3b+2) equation: 



39=2b+3(3b+2)

We move all terms to the left:

39-(2b+3(3b+2))=0



We calculate terms in parentheses: -(2b+3(3b+2)), so:

2b+3(3b+2)

We multiply parentheses

2b+9b+6

We add all the numbers together, and all the variables

11b+6

Back to the equation:

-(11b+6)



We get rid of parentheses

-11b-6+39=0

We add all the numbers together, and all the variables

-11b+33=0

We move all terms containing b to the left, all other terms to the right

-11b=-33

b=-33/-11

b=+3

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