39=2x-5(3x+15)

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Solution for 39=2x-5(3x+15) equation: 



39=2x-5(3x+15)

We move all terms to the left:

39-(2x-5(3x+15))=0



We calculate terms in parentheses: -(2x-5(3x+15)), so:

2x-5(3x+15)

We multiply parentheses

2x-15x-75

We add all the numbers together, and all the variables

-13x-75

Back to the equation:

-(-13x-75)



We get rid of parentheses

13x+75+39=0

We add all the numbers together, and all the variables

13x+114=0

We move all terms containing x to the left, all other terms to the right

13x=-114

x=-114/13

x=-8+10/13

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