39=3/11z+18

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Solution for 39=3/11z+18 equation: 



39=3/11z+18

We move all terms to the left:

39-(3/11z+18)=0



Domain of the equation: 11z+18)!=0

z∈R



We get rid of parentheses

-3/11z-18+39=0

We multiply all the terms by the denominator


-18*11z+39*11z-3=0

Wy multiply elements

-198z+429z-3=0

We add all the numbers together, and all the variables

231z-3=0

We move all terms containing z to the left, all other terms to the right

231z=3

z=3/231

z=1/77

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