39=3/11z=18

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Solution for 39=3/11z=18 equation: 



39=3/11z=18

We move all terms to the left:

39-(3/11z)=0



Domain of the equation: 11z)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

-(+3/11z)+39=0

We get rid of parentheses

-3/11z+39=0

We multiply all the terms by the denominator


39*11z-3=0

Wy multiply elements

429z-3=0

We move all terms containing z to the left, all other terms to the right

429z=3

z=3/429

z=1/143

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