39=5/7z+24

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Solution for 39=5/7z+24 equation: 



39=5/7z+24

We move all terms to the left:

39-(5/7z+24)=0



Domain of the equation: 7z+24)!=0

z∈R



We get rid of parentheses

-5/7z-24+39=0

We multiply all the terms by the denominator


-24*7z+39*7z-5=0

Wy multiply elements

-168z+273z-5=0

We add all the numbers together, and all the variables

105z-5=0

We move all terms containing z to the left, all other terms to the right

105z=5

z=5/105

z=1/21

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