39x+156=30x2+240x+480

Solution for 39x+156=30x2+240x+480 equation:

39x+156=30x^2+240x+480

We move all terms to the left:

39x+156-(30x^2+240x+480)=0

We get rid of parentheses

-30x^2+39x-240x-480+156=0

We add all the numbers together, and all the variables

-30x^2-201x-324=0

a = -30; b = -201; c = -324;
Δ = b2-4ac
Δ = -2012-4·(-30)·(-324)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-201)-39}{2*-30}=\frac{162}{-60}
=-2+7/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-201)+39}{2*-30}=\frac{240}{-60}
=-4
$