39x+36-12x2=0

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Solution for 39x+36-12x2=0 equation:



39x+36-12x^2=0
a = -12; b = 39; c = +36;
Δ = b2-4ac
Δ = 392-4·(-12)·36
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3249}=57$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-57}{2*-12}=\frac{-96}{-24} =+4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+57}{2*-12}=\frac{18}{-24} =-3/4 $

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