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3=((12)(x))/(12)+x
We move all terms to the left:
3-(((12)(x))/(12)+x)=0
Domain of the equation: 12+x)!=0determiningTheFunctionDomain -(12x/12+x)+3=0
We move all terms containing x to the left, all other terms to the right
x)!=-12
x!=-12/1
x!=-12
x∈R
We add all the numbers together, and all the variables
-(+x+12x/12)+3=0
We get rid of parentheses
-x-12x/12+3=0
We multiply all the terms by the denominator
-x*12-12x+3*12=0
We add all the numbers together, and all the variables
-12x-x*12+36=0
Wy multiply elements
-12x-12x+36=0
We add all the numbers together, and all the variables
-24x+36=0
We move all terms containing x to the left, all other terms to the right
-24x=-36
x=-36/-24
x=1+1/2
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