3=(+b)+(3/4+)

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Solution for 3=(+b)+(3/4+) equation: 



3=(+b)+(3/4+)

We move all terms to the left:

3-((+b)+(3/4+))=0

We add all the numbers together, and all the variables

-((+b)+(+3/4))+3=0

We multiply all the terms by the denominator


-((+b)+(+3+3*4))=0



We calculate terms in parentheses: -((+b)+(+3+3*4)), so:

(+b)+(+3+3*4)

We add all the numbers together, and all the variables

(+b)+15

We get rid of parentheses

b+15

Back to the equation:

-(b+15)



We get rid of parentheses

-b-15=0

We add all the numbers together, and all the variables

-1b-15=0

We move all terms containing b to the left, all other terms to the right

-b=15

b=15/-1

b=-15

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