3=(-33+3x)/7

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Solution for 3=(-33+3x)/7 equation: 



3=(-33+3x)/7

We move all terms to the left:

3-((-33+3x)/7)=0

We add all the numbers together, and all the variables

-((3x-33)/7)+3=0

We multiply all the terms by the denominator


-((3x-33)+3*7)=0



We calculate terms in parentheses: -((3x-33)+3*7), so:

(3x-33)+3*7

We add all the numbers together, and all the variables

(3x-33)+21

We get rid of parentheses

3x-33+21

We add all the numbers together, and all the variables

3x-12

Back to the equation:

-(3x-12)



We get rid of parentheses

-3x+12=0

We move all terms containing x to the left, all other terms to the right

-3x=-12

x=-12/-3

x=+4

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