3=(12b+4)/(b+3)

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Solution for 3=(12b+4)/(b+3) equation: 



3=(12b+4)/(b+3)

We move all terms to the left:

3-((12b+4)/(b+3))=0



Domain of the equation: (b+3))!=0

b∈R



We multiply all the terms by the denominator


-((12b+4)+3*(b+3))=0



We calculate terms in parentheses: -((12b+4)+3*(b+3)), so:

(12b+4)+3*(b+3)

We multiply parentheses

(12b+4)+3b+9

We get rid of parentheses

12b+3b+4+9

We add all the numbers together, and all the variables

15b+13

Back to the equation:

-(15b+13)



We get rid of parentheses

-15b-13=0

We move all terms containing b to the left, all other terms to the right

-15b=13

b=13/-15

b=-13/15

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