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3=(17-5)/t
We move all terms to the left:
3-((17-5)/t)=0
Domain of the equation: t)!=0We add all the numbers together, and all the variables
t!=0/1
t!=0
t∈R
-(12/t)+3=0
We get rid of parentheses
-12/t+3=0
We multiply all the terms by the denominator
3*t-12=0
We add all the numbers together, and all the variables
3t-12=0
We move all terms containing t to the left, all other terms to the right
3t=12
t=12/3
t=4
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