3=(18/z)=12

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Solution for 3=(18/z)=12 equation: 



3=(18/z)=12

We move all terms to the left:

3-((18/z))=0



Domain of the equation: z))!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

-((+18/z))+3=0

We multiply all the terms by the denominator


-((+18+3*z))=0



We calculate terms in parentheses: -((+18+3*z)), so:

(+18+3*z)

We add all the numbers together, and all the variables

(3z+18)

We get rid of parentheses

3z+18

Back to the equation:

-(3z+18)



We get rid of parentheses

-3z-18=0

We move all terms containing z to the left, all other terms to the right

-3z=18

z=18/-3

z=-6

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